The H.C.F. of \(\frac{9}{10}, \frac{12}{25}, \frac{18}{35}and\frac{21}{40} is:\) Options: A . &nbsp \(\frac{3}{5}\) B . &nbsp \(\frac{252}{5}\) C . &nbsp \(\frac{3}{1400}\) D . &nbsp \(\frac{63}{700}\)

The H.C.F. of \(\frac{9}{10}, \frac{12}{25}, \frac{18}{35}and\frac{21}{40}

Question

The H.C.F. of \(\frac{9}{10}, \frac{12}{25}, \frac{18}{35}and\frac{21}{40} is:\)

Options:

A . \(\frac{3}{5}\)

B . \(\frac{252}{5}\)

C . \(\frac{3}{1400}\)

D . \(\frac{63}{700}\)

Answer: Option C

\( Required H.F.C = \frac{H.F.C of 9,12,18,21}{L.C.M.of 10,25,35,40}= \frac{3}{1400}\)

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