Answer: Option C
:
C
We note that all 4 numbers have the same number of digits.
To findthe smallestnumberfrom the given numbers, we need to check the digit in the tens place for each number since the digits in the thousands and hundreds place are the same for all of them.
$\begin{array}{cc}\text{Number}& \text{Number of tens}\\ 28\underset{–}{0}9& 0\\ 28\underset{–}{9}9& 9\\ 28\underset{–}{5}0& 5\\ 28\underset{–}{9}0& 9\end{array}$
Since 9 > 5 > 0, the smallest number is P = 2809.
To find the largest number (which is either 2899 or 2890), we need to check the digit in the ones place.
Since 9> 0,the largest number is Q = 2899.