When resistance of 30Ω is connected to a battery, the current in the circu

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When resistance of 30

Ω

is connected to a battery, the current in the circuit is 0.4 A. if this resistance is replaced by 10

Ω

resistance, the current is 0.8 A. Then e.m.f. and the internal resistance of thebattery are

Options:

A . 10V,16Ω

B . 3V,20Ω

C . 16V,10Ω

D . 24V,32Ω

Answer: Option C
:
C

E = I_{1} [R_{1} + r] = I_{2} [R_{2} + r] 0.4 [30 + r] = 0.8 [10 + r] 30 + r = 20 + 2 r r = 10 E = 0.4 [30 + 10] E = 16 V

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