Question
/* sample.c */
#include<stdio.h>
int main(int argc, char *argv[])
{
int j;
j = argv[1] + argv[2] + argv[3];
printf("%d", j);
return 0;
}
What will be the output of the program (sample.c) given below if it is
executed from the command line (Turbo C in DOS)?
cmd> sample 1 2 3
/* sample.c */
#include<stdio.h>
int main(int argc, char *argv[])
{
int j;
j = argv[1] + argv[2] + argv[3];
printf("%d", j);
return 0;
}
Answer: Option C
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Here argv[1], argv[2] and argv[3] are string type. We have to convert the string to
integer type before perform arithmetic operation.
Example: j = atoi(argv[1]) + atoi(argv[2]) + atoi(argv[3]);
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