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What will be the output of the program ?


#include<stdio.h>
int main()
{
union a
{
int i;
char ch[2];
};
union a u;
u.ch[0]=3;
u.ch[1]=2;
printf("%d, %d, %d\n" , u.ch[0], u.ch[1], u.i);
return 0;
}
Options:
A .  3, 2, 515
B .  515, 2, 3
C .  3, 2, 5
D .  515, 515, 4
Answer: Option A

The system will allocate 2 bytes for the union.

The statements u.ch[0]=3; u.ch[1]=2; store data in memory as given below.

What Will Be The Output Of The Program ?#include<stdio.h&...

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