Question
What will be the output of the program?
#include<stdio.h>
int main()
{
int i=2;
int j = i + (1, 2, 3, 4, 5);
printf("%d\n", j);
return 0;
}
What will be the output of the program?
#include<stdio.h>
int main()
{
int i=2;
int j = i + (1, 2, 3, 4, 5);
printf("%d\n", j);
return 0;
}
Answer: Option B
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Because, comma operator used in the expression i (1, 2, 3, 4, 5). The comma
operator has left-right associativity. The left operand is always evaluated first,
and the result of evaluation is discarded before the right operand is evaluated.
In this expression 5 is the right most operand, hence after evaluating expression
(1, 2, 3, 4, 5) the result is 5, which on adding to i results into 7.
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