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Question
What will be the normal equation for z if the equations are given as 3x+9y+4z-43=0, 2x+6y+z-5=0. Assume these are having equal weights.
Options:
A .  17x+42y+47z-178=0
B .  14x+17y+42z-178=0
C .  14x+42y+17z-178=0
D .  42x+14y+17z-178=0
Answer: Option C
Answer: (c).14x+42y+17z-178=0

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