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Question

What will be the maximum sum of 44, 42, 40, ... ?


Options:
A .  502
B .  504
C .  506
D .  500
Answer: Option C

The maximum sum is the sum of 44, 42,--------2.

The sum of 'n' terms of an AP  

= `n/2` [2a + ( n - 1 )d]

In this case, n = 22, a = 2 and d = 2 

`:.`  Sum = 11[4 + 2l x 2] = 11 x 46 = 506



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