Question
What will be the maximum sum of 44, 42, 40, ... ?
Answer: Option C
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The maximum sum is the sum of 44, 42,--------2.
The sum of 'n' terms of an AP
= `n/2` [2a + ( n - 1 )d]
In this case, n = 22, a = 2 and d = 2
`:.` Sum = 11[4 + 2l x 2] = 11 x 46 = 506
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