Question
What is the output of this program?
#include < iostream >
using namespace std;
int main()
{
char arr[20];
int i;
for(i = 0; i < 10; i++)
*(arr + i) = 65 + i;
*(arr + i) = '\0';
cout
Answer: Option A
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Each time we are assigning 65 + i. In first iteration i = 0 and 65 is assigned. So it will print from A to J.
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