Question
What is the output of the code shown below?A = [[1, 2, 3], [4, 5, 6], [7, 8, 9]][A[i][len(A)-1-i] for i in range(len(A))]
Answer: Option C
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This expression scales the common index to fetch A[0][2], A[1][1], etc. We assume the matrix has the same number of rows and columns.
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