Question
What is the number of oxygen atoms present in 126 g of HNO3?
Answer: Option A
:
A
Molecular mass of HNO3 = atomic mass of hydrogen + atomic mass of nitrogen + 3× atomic mass of oxygen = 1 + 14 + (3 × 16) = 63 u.
∙ In 1 molecule of HNO3 we have 3 atoms of oxygen.
∙ 1 mole of HNO3 contains 3 moles of oxygen atoms. So, in 2 moles of HNO3 we will have 6 moles of oxygen atoms.
∙ One mole of a substance contains 6.022×1023 particles. So, the number of atoms in 126 g of HNO3= 6×6.022×1023 = 36.132×1023 atoms.
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:
A
Molecular mass of HNO3 = atomic mass of hydrogen + atomic mass of nitrogen + 3× atomic mass of oxygen = 1 + 14 + (3 × 16) = 63 u.
Number of moles = Given massGram molecular mass
Moles of HNO3 = 12663 = 2 moles
∙ In 1 molecule of HNO3 we have 3 atoms of oxygen.
∙ 1 mole of HNO3 contains 3 moles of oxygen atoms. So, in 2 moles of HNO3 we will have 6 moles of oxygen atoms.
∙ One mole of a substance contains 6.022×1023 particles. So, the number of atoms in 126 g of HNO3= 6×6.022×1023 = 36.132×1023 atoms.
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