Question
Two slits separated by 0.200 mm are to be sued in Young's double – slit experiment. Immediately behind the slits in a lens of focal length 0.500 m used to form the interference pattern on a screen located in the focal plane of the lens. What is the wavelength of a monochromatic light source used to illuminate the slits if adjacent maxima of the interference pattern are separated by 1.00 mm?
Answer: Option A
:
A
β=λDd,D=0.5m,d=0.2×10−3m,β=1×10−3m
So answer is 400 nm
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:
A
β=λDd,D=0.5m,d=0.2×10−3m,β=1×10−3m
So answer is 400 nm
Was this answer helpful ?
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