Question
Two points A and B have coordinates (1, 0) and (-1, 0) respectively and Q is a point which satisfies the relation
AQ - BQ = ± 1. The locus of Q is
AQ - BQ = ± 1. The locus of Q is
Answer: Option B
:
B
According to the given condition
√(x−1)2+y2−√(x+1)2+y2 = ±1
On squaring both sides, we get
2x2+2y2+1=2√(x−1)2+y2√(x+1)2+y2
Again on squaring, we get 12x2−4y2=3.
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:
B
According to the given condition
√(x−1)2+y2−√(x+1)2+y2 = ±1
On squaring both sides, we get
2x2+2y2+1=2√(x−1)2+y2√(x+1)2+y2
Again on squaring, we get 12x2−4y2=3.
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