Three times the first of three consecutive odd integers is 3 more than twice the

Question

Three times the first of three consecutive odd integers is 3 more than twice the third. The third integer is:

Options:

A . 9

B . 11

C . 13

D . 15

Answer: Option D

Let the three integers be x, x + 2 and x + 4.

Then, 3x = 2(x + 4) + 3 \(\Leftrightarrow\) x = 11.

Therefore Third integer = x + 4 = 15.

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