Question
- Three persons begin to walk around a circular track. They complete their revolutions in \(15\frac{1}{6}\)seconds, \(16\frac{1}{4}\) seconds and \(18\frac{2}{3}\)seconds respectively. After what time will they be together at the starting point again?
Answer: Option D
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Submit Your Solution Below and Earn Points !
=L.C.M OF (91/6,65/4,56/3)
={L.C.M OF(91,65,56)}/{H.C.F OF(6,4,3)}
=3640/1
=3640 Sec.