Question
The value of sin[2tan−1(13)]+cos[tan−1(2√2)]=
Answer: Option B
:
B
sin[2tan−1(13)]+cos[tan−1(2√2)]
=sin[tan−1231−19]+cos[tan−1(2√2)]
=sin[tan−134]+cos[tan−12√2]
=tan−12√2=cos−113
Alsotan−134=sin−135
=35+13=1415.
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:
B
sin[2tan−1(13)]+cos[tan−1(2√2)]
=sin[tan−1231−19]+cos[tan−1(2√2)]
=sin[tan−134]+cos[tan−12√2]
=tan−12√2=cos−113
Alsotan−134=sin−135
=35+13=1415.
Was this answer helpful ?
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