Question
The time taken by a particle executing simple harmonic motion of time period T to move from the mean position to half the maximum displacement is
Answer: Option D
:
D
Let the displacement of the particle be given by x = A sin ω t = A sin (2πtT) i.e., when x = 0, t0=0.
When x = A/2, the value of t is given by A2=Asin2πt1T;sin2πt1T=12
2πt1T=π6ort1=T12;t1−t0=T12−0=T12
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:
D
Let the displacement of the particle be given by x = A sin ω t = A sin (2πtT) i.e., when x = 0, t0=0.
When x = A/2, the value of t is given by A2=Asin2πt1T;sin2πt1T=12
2πt1T=π6ort1=T12;t1−t0=T12−0=T12
Was this answer helpful ?
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