The sum of three consecutive numbers is 36 . Find the numbers. Options: A . &nbsp12,13,14 B . &nbsp10,11,12 C . &nbsp11,12,13 D . &nbsp13,12,11

Answer: Option C : C Let the first number be a . So the three consecutive numbers will be a , a + 1 , a + 2 . a +a +1 +a +2 = 36 ⇒ 3a +3 = 36 ⇒ 3a = 36 -3 = 33 ⇒ a = 33 3 = 11 So, the three consecutive numbers will be 11 , 12 , 13 .

The sum of three consecutive numbers is 36. Find the numbers.

Question

The sum of three consecutive numbers is

36

. Find the numbers.

Options:

A . 12,13,14

B . 10,11,12

C . 11,12,13

D . 13,12,11

Answer: Option C
:
C
Let the first number be

a

.
So the three consecutive numbers will be

a, a + 1, a + 2

a +a +1 +a +2 = 36

\Rightarrow

3a +3 = 36

\Rightarrow

3a = 36 -3 = 33

\Rightarrow

a = \frac{33}{3} = 11

So, the three consecutive numbers will be

11, 12, 13

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