Question
The sum of the digits of a 3-digit number is subtracted from the number. The resulting number is:
Answer: Option B
- Let the 3-digit number be xyz. Then,
(100x + 10y + z) - (x + y + z) = 99x + 9y = 9 (11x + y), Which is divisible by 9
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- Let the 3-digit number be xyz. Then,
(100x + 10y + z) - (x + y + z) = 99x + 9y = 9 (11x + y), Which is divisible by 9
Was this answer helpful ?
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