The secondary unbalanced force due to inertia of reciprocating parts in a recipr

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The secondary unbalanced force due to inertia of reciprocating parts in a reciprocating engine is given by (where m = Mass of reciprocating parts, $$\omega $$ = Angular speed of crank, r = Radius of crank, $$\theta $$ = Angle of inclination of crank with the line of stroke and n = Ratio of the length of connecting rod to radius of crank)

Options:

A . $${\text{m}}{\omega ^2}{\text{r}}\sin \theta $$

B . $${\text{m}}{\omega ^2}{\text{r}}\cos \theta $$

C . $${\text{m}}{\omega ^2}{\text{r}}\frac{{\sin 2\theta }}{{\text{n}}}$$

D . $${\text{m}}{\omega ^2}{\text{r}}\frac{{\cos2\theta }}{{\text{n}}}$$

Answer: Option D

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