The ratio of BCCC′ is 3:5. What will the ratio of corresponding sides be if t

Question

The ratio of

\frac{B C}{C C^{'}}

is 3:5. What will the ratio of corresponding sides be if triangles ABC and A'BC' are similar? Given that BC and BC' lie
on the same ray BY.

Options:

A . 5:8

B . 3:8

C . 8:5

D . 8:3

Answer: Option B
:
B

SinceBC and BC' lie on the same line, the points B, C andC' are collinear.

\frac{B C}{C C^{'}}

\frac{3}{5}

Therefore

\frac{B C^{'}}{B C}

\frac{B C + C C^{'}}{B C}

\frac{B C^{'}}{B C}

= 1+

\frac{C C^{'}}{B C}

\frac{C C^{'}}{B C}

\frac{5}{3}

.
So

\frac{B C^{'}}{B C} = \frac{8}{3}

∴ \frac{B C}{B C^{'}}

\frac{3}{8}

The ratio of corresponding sides of triangles

A B C

and

A^{'} B C^{'}

\frac{3}{8}

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