The rate equation for _______________ inhibition is given by \(V=\frac{V_{max} [S]}{K_m (1+\frac{[P]}{K_p})+[S]}\). Options: A . &nbspsubstrate B . &nbspnon-competitive C . &nbspproduct D . &nbspcompetitive

The rate equation for _______________ inhibition is given by \(V=\frac{V

Question

The rate equation for _______________ inhibition is given by \(V=\frac{V_{max} [S]}{K_m (1+\frac{[P]}{K_p})+[S]}\).

Options:

A . substrate

B . non-competitive

C . product

D . competitive

Answer: Option C
Answer: (c).product

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Question 1. In the following diagram, what does enzyme Z represent?....

Question 2. The following rate equation is given by ___________ inhibition. \(V=\frac{\left (\frac{V_{max}}{1+\frac{[I]}{K_i’}}\r....given by ___________ inhibition. \(V=\frac{\left (\frac{V_{max}}{1+\frac{[I]}{K_i’}}\right ) [S]}{\left (\frac{K_m}{1+\frac{[I]}{K_i’}}\right )+[S]}\)

Question 3. What does the following graph represent?....

Question 4. The following graph represents the effect of ____________ on activity of an enzyme catalyzed reaction.....

Question 5. In the following diagram, which inhibition is represented?....

Question 6. The following diagram represents _______________ inhibition.....

Question 7. In the following diagram, which kind of inhibition is represented?....

Question 8. Major drawback of utilizing enzymes is _________....

Question 9. Which of the following is an advantage of enzymes over chemical catalysts?....

Question 10. ____________ mediates the synthetic and degradative reactions carried out by living organism.....

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