Question
The range of the function f(x)=2+x2−x,x≠2 is
Answer: Option B
:
B
y=2+x2−x⇒2y−yx=2+x⇒x(y+1)=2y−2⇒x=2y−2y+1⇒f−1(x)=2x−2x+1
∴ Range of f= Domain of f−1=R−{−1}
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:
B
y=2+x2−x⇒2y−yx=2+x⇒x(y+1)=2y−2⇒x=2y−2y+1⇒f−1(x)=2x−2x+1
∴ Range of f= Domain of f−1=R−{−1}
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