Question
The radius of a hemispherical bowls is 6 cm. The capacity of the bowl is $$\left( {{\text{Take }}\pi = \frac{{22}}{7}} \right)$$
Answer: Option B
Radius of hemisphere bowl = 6 cm
∴ Volume of hemisphere :
$$\eqalign{
& = \frac{2}{3}\pi {r^3} \cr
& = \frac{2}{3} \times \frac{{22}}{7} \times 6 \times 6 \times 6 \cr
& = \frac{{9504}}{{21}} \cr
& = 452.57{\text{ c}}{{\text{m}}^3} \cr} $$
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Radius of hemisphere bowl = 6 cm
∴ Volume of hemisphere :
$$\eqalign{
& = \frac{2}{3}\pi {r^3} \cr
& = \frac{2}{3} \times \frac{{22}}{7} \times 6 \times 6 \times 6 \cr
& = \frac{{9504}}{{21}} \cr
& = 452.57{\text{ c}}{{\text{m}}^3} \cr} $$
Was this answer helpful ?
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