Question
The perimeter of a triangular field is 420 m and its sides are in the ratio 6:7:8. Find the area of the triangular field.
Answer: Option D
:
D
Let the sides be 6x, 7x, 8x.
Then, 6x+7x+8x=420
⇒21x=420
x=20
∴ the sides are:
a =120 m, b =140 m, c =160 m
Semi-perimeter s = 4202=210 m
A=√s(s−a)(s−b)(s−c)
=√210(210−120)(210−140)(210−160)
=√210×90×70×50
=2100√15 m2
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:
D
Let the sides be 6x, 7x, 8x.
Then, 6x+7x+8x=420
⇒21x=420
x=20
∴ the sides are:
a =120 m, b =140 m, c =160 m
Semi-perimeter s = 4202=210 m
A=√s(s−a)(s−b)(s−c)
=√210(210−120)(210−140)(210−160)
=√210×90×70×50
=2100√15 m2
Was this answer helpful ?
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