The sum of the digits of the given number is 4 + 5 + 6 + 3 + 1 + 8 = 27 which is divisible by 3.
Hence, the given number is divisible by 3.
The last digit of the number is even. Hence, it is divisible by 2.
Since the number is divisible by both 3 and 2, it is divisible by 6.
A number is divisible by 11 , if  the difference between the sum of its digits in even places and the sum of its digits in odd places is either 0 or divisible by 11.
Here, sum of digits in even places
= 1 + 6 + 4 = 11
Sum of digits in odd places
= 8 + 3 + 5 = 16
Difference = 16 -11 = 5 which is not divisible by 11. 
$\therefore$ The given number is not divisible by 11.