The magnetic field at the centre of the circular coil carrying current of 4A is Options: A . &nbsp8π3×10−5T B . &nbsp8π3×10−4T C . &nbsp2π×10−5T D . &nbsp2π×10−4T

Answer: Option C : C B = μ 0 i 2 r [ θ 2 π ] = 4 π 10 − 7 × 4 2 × 3 × 10 − 2 [ 3 π 2 2 π ] = 2 π × 10 − 5 T

The magnetic field at the centre of the circular coil carrying current of 4A is

Question

The magnetic field at the centre of the circular coil carrying current of 4A is

Options:

A . 8π3×10−5T

B . 8π3×10−4T

C . 2π×10−5T

D . 2π×10−4T

Answer: Option C
:
C

B = \frac{μ_{0} i}{2 r} [\frac{θ}{2 π}] = \frac{4 π 10^{- 7} \times 4}{2 \times 3 \times 10^{- 2}} [\frac{\frac{3 π}{2}}{2 π}] = 2 π \times 10^{- 5} T

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