Question
The length of the longest rod that can be placed in a room of dimensions 10 m × 10 m × 5 m is :
Answer: Option B
Required length :
$$\eqalign{
& = \sqrt {{{\left( {10} \right)}^2} + {{\left( {10} \right)}^2} + {{\left( 5 \right)}^2}} \,m \cr
& = \sqrt {225} \,m \cr
& = 15\,m \cr} $$
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Required length :
$$\eqalign{
& = \sqrt {{{\left( {10} \right)}^2} + {{\left( {10} \right)}^2} + {{\left( 5 \right)}^2}} \,m \cr
& = \sqrt {225} \,m \cr
& = 15\,m \cr} $$
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