Question
The least multiple of 7 which leaves a remainder of 4, when divided by 6, 9, 15 and 18 is ___.
Answer: Option D
:
D
We first find theL.C.M of 6, 9, 15 and 18, which is90.
Forgetting remainder 4, we need to add 4 to it.
i.e.,90+4 = 94.
But, 94 is not divisible by7. So, we proceed with thenext multiple of 90, which is 180.
Adding 4 to 180, we get 184, which is also not divisible by 7.
The next multiple of 90 is270.
Adding 4 to 270, we get274, againnot divisible by 7.
The next multiple of 90 is 360.
Adding 4 to it gives us 364, divisible by 7(as 3647=52).
Hence, the answer is 364.
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:
D
We first find theL.C.M of 6, 9, 15 and 18, which is90.
Forgetting remainder 4, we need to add 4 to it.
i.e.,90+4 = 94.
But, 94 is not divisible by7. So, we proceed with thenext multiple of 90, which is 180.
Adding 4 to 180, we get 184, which is also not divisible by 7.
The next multiple of 90 is270.
Adding 4 to 270, we get274, againnot divisible by 7.
The next multiple of 90 is 360.
Adding 4 to it gives us 364, divisible by 7(as 3647=52).
Hence, the answer is 364.
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