The efficiency of the

Question

The efficiency of the Carnot cycle is (where T₁ and T₂ = Highest and lowest temperature during the cycle)

Options:

A . `T_1/T_2 - 1`

B . `1 - T_1/T_2`

C . `1 - T_2/T_1`

D . `1+T_2/T_1`

Answer: Option C

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