Question
The diagonal of a rectangle is \(\sqrt{41}\) cm and its area is 20 sq. cm. The perimeter of the rectangle must be:
Answer: Option B
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\(\sqrt{l^{2}+b^{2}}\)
Also, lb = 20.
(l + b)2 = (l2 + b2) + 2lb = 41 + 40 = 81
(l + b) = 9.
Perimeter = 2(l + b) = 18 cm.
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