Question
The conjugate of (2+i)23+i , in the form of a+ib, is
Answer: Option C
:
C
z = (2+i)23+i=3+4i3+i×3−i3−i=1310+i910
Conjugate = 1310−i910.
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:
C
z = (2+i)23+i=3+4i3+i×3−i3−i=1310+i910
Conjugate = 1310−i910.
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