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Question
The centre of gravity of the trapezium as shown in below figure from the side is at a distance of
Options:
A .  (h/3) × [(b + 2a)/(b + a)]
B .  (h/3) × [(2b + a)/(b + a)]
C .  (h/2) × [(b + 2a)/(b + a)]
D .  (h/2) × [(2b + a)/(b + a)]
Answer: Option A

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