The cartesian equation of trajectory is(where u = Velocity of projection, `alpha` = Angle of projection, and x , y = Co-ordinates of any point on the trajectory after t seconds.) Options: A . &nbsp`y = (gx^2)/(2u^2 cos 2 alpha) + x tan alpha` B . &nbsp`y = (gx^2)/(2u^2 cos 2 alpha) - x tan alpha` C . &nbsp`y = x tan alpha - (gx^2)/(2u^2 cos alpha)` D . &nbsp`y = x tan alpha + (gx^2)/(2u^2 cos alpha)`

The cartesian equation

Question

The cartesian equation of trajectory is(where u = Velocity of projection, `alpha` = Angle of projection, and x, y = Co-ordinates of any point on the trajectory after t seconds.)

Options:

A . `y = (gx^2)/(2u^2 cos 2 alpha) + x tan alpha`

B . `y = (gx^2)/(2u^2 cos 2 alpha) - x tan alpha`

C . `y = x tan alpha - (gx^2)/(2u^2 cos alpha)`

D . `y = x tan alpha + (gx^2)/(2u^2 cos alpha)`

Answer: Option C

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