Question
The average of three consecutive odd numbers is 12 more than one third of the first of these numbers. What is the last of the three numbers ?
Answer: Option B
Answer: (b)If the smallest number be x, then$x/3$+12 = x+2⇒ x + 36 = 3x + 6⇒ 3x – x = 36 – 6⇒ 2x = 30 ⇒ x = 15∴ Third number = 15 + 4 = 19
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Answer: (b)If the smallest number be x, then$x/3$+12 = x+2⇒ x + 36 = 3x + 6⇒ 3x – x = 36 – 6⇒ 2x = 30 ⇒ x = 15∴ Third number = 15 + 4 = 19
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