Question
The area of a square field is 576m2. Find [4 MARKS]
(i) The length of its sides
(ii) The length of its perimeter
(iii) Cost of fixing a fence along the boundary of the field at the rate of Rs 3.20 per metre.
(i) The length of its sides
(ii) The length of its perimeter
(iii) Cost of fixing a fence along the boundary of the field at the rate of Rs 3.20 per metre.
Answer:
:
Steps: 2 Marks
Formula: 1 Mark
Answer: 1 Mark
(i) Let l be the length of the square
⇒ Area of square = l2
⇒l2=576
⇒l=24m
(ii)Perimeter of square = 4l
⇒4×(24)=96m
(iii) Cost of fixing a fence
=₹(96×3.20)=₹307.20
Was this answer helpful ?
:
Steps: 2 Marks
Formula: 1 Mark
Answer: 1 Mark
(i) Let l be the length of the square
⇒ Area of square = l2
⇒l2=576
⇒l=24m
(ii)Perimeter of square = 4l
⇒4×(24)=96m
(iii) Cost of fixing a fence
=₹(96×3.20)=₹307.20
Was this answer helpful ?
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