Question
tan[2tan−1(15)−π4]=
Answer: Option D
:
D
tan[2tan−1(15)−π4]=tan[tan−1251−125−tan−1(1)]
=tan[tan−1512−tan−1(1)]=tantan−1(512−11+512)=−717
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:
D
tan[2tan−1(15)−π4]=tan[tan−1251−125−tan−1(1)]
=tan[tan−1512−tan−1(1)]=tantan−1(512−11+512)=−717
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