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Suppose y varies as the sum of two quantities of which one varies directly as x and the other inversely as x. If y = 6 when x = 4 and y = $${\text{3}}\frac{{\text{1}}}{{\text{3}}}$$ when x = 3, then the relation between x and y is -
Options:
A .  $$y = 2x - \frac{8}{x}$$
B .  $$y = x + \frac{4}{x}$$
C .  $$y = 2x + \frac{4}{x}$$
D .  $$y = 2x + \frac{8}{x}$$
Answer: Option A

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