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Resolving power of a microscope is
Options:
A .  1.22λ2a\frac{1.22λ}{2a}2a1.22λ​
B .  2a1.22 λ\frac{2a}{1.22\ \lambda}1.22 λ2a​
C .  (2nsin⁡β)1.22λ\frac{\left(2n\sin\beta\right)}{1.22\lambda}1.22λ(2nsinβ)​
D .  1.22λ2n sin⁡β\frac{1.22\lambda}{2n\ \sin\beta}2n sinβ1.22λ​
Answer: Option C

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