Answer: Option B
:
B and C
The given compound is an unsaturated hydrocarbon because it contains a $\text{C=C}$ bond. It is an alkene having the general formula ${\text{C}}_{\text{n}}{\text{H}}_{\text{2n}}$. The given compound is numbered as shown below.
$\underset{6}{{\text{CH}}_3}-\underset{5}{{\text{CH}}_2}-\underset{4}{{\text{CH}}_2}-\underset{3}{\text{CH}}=\underset{2}{\text{CH}}-\underset{1}{{\text{CH}}_3}$
$\bullet$ The compound has six carbon atoms in it and hence, the word root is 'hex'.
$\bullet$ It has a double bond between the second and the third carbon atoms and hence, the suffix will be '2-ene'.
Therefore, the IUPAC name of the given compound is hex-2-ene.