Question
N= 4! + 5!+6!.........200!. Find the last two digits of N
Answer: Option C
:
C
After 10!, the factorials end with 0 as the last two digits. We thusneed to find the last two digits from 4! To 9! Only
4!+5!+6!....9!= 24+120 + 720 + 5040 + 40320 + 362880 = ___04
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:
C
After 10!, the factorials end with 0 as the last two digits. We thusneed to find the last two digits from 4! To 9! Only
4!+5!+6!....9!= 24+120 + 720 + 5040 + 40320 + 362880 = ___04
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