Question
If 5y–5(y−1)=100, then what is the value of (3y)y?
Answer: Option D
:
D
5y−5y5=100; 5y(1−15)=52×4; 5y(45)=52×4
⟹5(y−1)×4=52×4;y−1=2; y=3. Answer is (3y)y=(9)3=729.
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D
5y−5y5=100; 5y(1−15)=52×4; 5y(45)=52×4
⟹5(y−1)×4=52×4;y−1=2; y=3. Answer is (3y)y=(9)3=729.
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