Let p, q be the roots of the equation x2−3x+2=0. The quadratic equation

Question

Let p, q be the roots of the equation

x^{2} - 3 x + 2 = 0.

The quadratic equation having roots 2p and 2q is:

Options:

A . x2−3x+4=0

B . x2−6x−8=0

C . x2−6x+4=0

D . x2−6x+8=0

Answer: Option D
:
D
Substitute x by

(\frac{x}{2})

The equation becomes:

{(\frac{x}{2})}^{2} - 3 (\frac{x}{2}) + 2 = 0, x^{2} - 6 x + 8 = 0.

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