int x = 0, y = 0 , z = 0 ; x = (++x + y-- ) * z++; What will be the value of "x" after execution ? Options: A . &nbsp-2 B . &nbsp-1 C . &nbsp0 D . &nbsp1 E . &nbsp2

int x = 0, y = 0 , z = 0 ; x = (++x + y-- ) * z++; What will be the value of "x"

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Int x = 0, y = 0 , z = 0 ;
x = (++x + y-- ) * z++;
What will be the value of "x" after execution ?

Answer: Option C

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