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In the following figure, a body of mass 'm' is tied at one end of a light string and this string is wrapped around the solid cylinder of mass 'M' and radius 'R'. At the moment, t = 0 the system starts moving. If the friction is negligible, angular velocity at time, t would be
Options:
A .  mgRt(M+m) 
B .  2MgtR(M+2m) 
C .  2mgtR(M−2m) 
D .  2mgtR(M+2m) 
Answer: Option D
:
D
We know the tangential acceleration a=g1+ImR2=g1+1/2MR2mR2=2mg2m+M [AsI=12MR2forcylinder]
After time t, linear velocity of mass m,v=u+at=0+2mgt2m+M
So angular velocity of the cylinder ω=vR=2mgtR(M+2m).
In The Following Figure, A Body Of Mass 'm' Is Tied At One E...

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