In the circuit given below potential difference across 6 μ F capacitor is

Question

In the circuit given below potential difference across 6

μ

F capacitor is

Options:

A . 8 V

B . 4 V

C . 6 V

D . 3 V

Answer: Option B
:
B

q = C_{1} V_{1} = C^{1} V_{2}

\frac{V_{1}}{V_{2}} = \frac{C^{1}}{C_{1}} = \frac{9}{4.5} = \frac{2}{1}

\frac{V_{1} + V_{2}}{V_{2}} = \frac{2 + 1}{1}

V_{2} = \frac{12}{3} = 4 V

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