In the below figure if AP=BP, AQ=BQ, then AM=BM?
In the given figure,AP = BP (Given)AQ = BQ (Given)PQ is common.So, Δ PAQ ≅ Δ PBQ (SSS rule).⇒∠ APQ=∠ BPQ (CPCT).Also, AP = BP (Given) and PM is commonHence, △ PMA ≅ △PMB (SAS Rule)
So, AM = BM
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