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Answer:
:
Given, ∠FIS=60∘
Now, ∠FTS=∠FIS=60∘ [∵ opposite angles of a parallelogram are equal]
Now, FT∥IS and TI is a transversal, therefore ∠FIO=∠STO=35∘ [alternate angles]
Also, ∠FOT+∠SOT=180∘ [linear pair]
⇒110∘+∠SOT=180∘
⇒∠SOT=70∘
In ΔTOS,∠TSO+∠OTS+∠TOS=180∘ [angle sum property of triangle]
∴∠OST=180∘−(70∘+35∘)=75∘
In ΔFST,∠SFT+∠FTS+∠TSF=180∘ [angle sum property of triangle]
⇒∠SFT=180∘−(60∘+75∘)∴∠SFT=45∘
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:
Given, ∠FIS=60∘
Now, ∠FTS=∠FIS=60∘ [∵ opposite angles of a parallelogram are equal]
Now, FT∥IS and TI is a transversal, therefore ∠FIO=∠STO=35∘ [alternate angles]
Also, ∠FOT+∠SOT=180∘ [linear pair]
⇒110∘+∠SOT=180∘
⇒∠SOT=70∘
In ΔTOS,∠TSO+∠OTS+∠TOS=180∘ [angle sum property of triangle]
∴∠OST=180∘−(70∘+35∘)=75∘
In ΔFST,∠SFT+∠FTS+∠TSF=180∘ [angle sum property of triangle]
⇒∠SFT=180∘−(60∘+75∘)∴∠SFT=45∘
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