Question
In how many ways can a group of 5 men and 2 women be made out of a total of 7 men and 3 women?
Answer: Option A
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Required number of ways = (7C5 x 3C2) = (7C2 x 3C1) = \(\left(\frac{7\times6}{2\times1}\times3\right)= 63.\)
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