In how many ways can 3 men and their wives be made stand in a line such that none of the 3 men stand in a position that is ahead of his wife? Options: A . &nbsp$$\frac{{6!}}{{3! \times 3! \times 3!}}$$ B . &nbsp$$\frac{{6!}}{{2! \times 2!}}$$ C . &nbsp$$\frac{{6!}}{{2! \times 2! \times 2!}}$$ D . &nbsp$$\frac{{6!}}{{2! \times 3!}}$$

In how many ways can 3 men and their wives be made stand in a line such that non

Question

In how many ways can 3 men and their wives be made stand in a line such that none of the 3 men stand in a position that is ahead of his wife?

Options:

A . $$\frac{{6!}}{{3! \times 3! \times 3!}}$$

B . $$\frac{{6!}}{{2! \times 2!}}$$

C . $$\frac{{6!}}{{2! \times 2! \times 2!}}$$

D . $$\frac{{6!}}{{2! \times 3!}}$$

Answer: Option C

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